Answered You can buy a ready-made answer or pick a professional tutor to order an original one.

QUESTION

Newton law of cooling equation

Newton law of cooling equation

Show more
danielmairush
danielmairush
  • @
ANSWER

Tutor has posted answer for $10.00. See answer's preview

$10.00

************ Law ** Cooling ****** **** the **** of change ** *** temperature ** ** ****** ** ************ ** *** difference ******* *** *** *********** *** the ******* *********** *** *** temperature ** *** **************

************

*** of ******* ** **** ** model *** temperature ****** ** an object ** **** *********** ****** ** ** environment ** a different temperature *** law ****** that *****

*

**

***

*********** ** the ****** ** time * * ** the *********** ** *** surrounding *********** ********** *** * ** * ******** ** *************** **** **** *** **** is **** *** **** ** change ** *********** is ************ to the difference ******* *** temperature ** *** ****** *** **** ** *** surrounding ************ ** ***** ** ***

***

******** equation ** ********* **** ** *** *** ** **** ***** *** ************ ******** *** ***** are ***** ****** Separate *** ********* *** ***

***

*******

on

***

side *** *** *** ******* ** *** other side *** ********* can be ** ****** ***** ****************** both sides ***** in the ******** **** **

solve

***

T

**

***

have * useful

equation

****

you

are

******* **** Newton's *** ** ******* remember **** t

**

the

********

The

*****

*******

R * C *** all ********* ** ***** ** **** the *********** ** *** object ** * ***** **** all of the constants must first have numerical ******

or Buy custom answer
  • @
  • 6 orders completed
ANSWER

Tutor has posted answer for $10.00. See answer's preview

$10.00

****** **** *** **** ** ****** ** *** temperature ** an ****** ** ************ ** *** ********** ******* its *** *********** and *** ******* *********** (ie the *********** ** its ************* ******** *** ***** * ********* ***** an instantaneous **** ** ****** ** *** ************

See ****** ******

****

*

*********** ** ** ****** at * certain **** ******* K) * *

time **** Ts =

*********** ** *** ************ ******* *** ** =

******** *********** of *** object ******* *** k *

a cooling constant ******** to the ****** ****** ******** Law

**

******* ******* *********** ** * ***

** **** starts at a *********** ** **** * *** *** *********** *********** ** 2930 * ** the ******* constant is * = 000150 *** **** **** *** *********** of the *** of **** be ***** *** ********* ******* *** ****

cools

*** 200 ******* which **** t=200min*60s/1min t * ****

**

***

temperature of *** ****

***** *** ***** **** *** be ***** using *** formula: T(t) * Ts + ***

* ** ) e(-kt) T(1200 ** * 2930 *

* ***** K-2930 ** *********** ********* **** T(1200 ** = **** *

* ***** K-2930 ** e(-1800) T(1200 ** = **** K

* ***** K-2930 ********** ****** ** * **** *

* (100 ********** T(1200 ** * **** K

+ *** ** ****** ** *** 2947 **

***** ** ******* *** ******

temperature ** 2947 *

Click here to download attached files: 3679356_m.png
Click here to download attached files: unit-35-16-638.jpg
or Buy custom answer
paulkoome
paulkoome
  • @
  • 732 orders completed
ANSWER

Tutor has posted answer for $10.00. See answer's preview

$10.00

******** IN WORD *******

Click here to download attached files: NEWTON LAW OF COOLING EQUATION.docx
or Buy custom answer
  • @
  • 17 orders completed
ANSWER

Tutor has posted answer for $10.00. See answer's preview

$10.00

** ****** provide your ******** feedback ***** ** *****

****** ******* me *** **** future work and ***** **** ******* to ***

**

**** ** any ***** ****** **** **** ** write on: *************************************

*****

***

Click here to download attached files: Newton law of cooling equation.docx
or Buy custom answer
ANSWER

Tutor has posted answer for $10.00. See answer's preview

$10.00

**** ****** attached with the **** ********** ** *** *******

Click here to download attached files: The Newton law of coolin.docx
or Buy custom answer
LEARN MORE EFFECTIVELY AND GET BETTER GRADES!
Ask a Question