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# Newton law of cooling equation

Newton law of cooling equation

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************ Law ** Cooling ****** **** the **** of change ** *** temperature ** ** ****** ** ************ ** *** difference ******* *** *** *********** *** the ******* *********** *** *** temperature ** *** **************

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****** **** *** **** ** ****** ** *** temperature ** an ****** ** ************ ** *** ********** ******* its *** *********** and *** ******* *********** (ie the *********** ** its ************* ******** *** ***** * ********* ***** an instantaneous **** ** ****** ** *** ************

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*********** ** ** ****** at * certain **** ******* K) * *

time **** Ts =

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******** *********** of *** object ******* *** k *

a cooling constant ******** to the ****** ****** ******** Law

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******* ******* *********** ** * ***

** **** starts at a *********** ** **** * *** *** *********** *********** ** 2930 * ** the ******* constant is * = 000150 *** **** **** *** *********** of the *** of **** be ***** *** ********* ******* *** ****

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*** 200 ******* which **** t=200min*60s/1min t * ****

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temperature of *** ****

***** *** ***** **** *** be ***** using *** formula: T(t) * Ts + ***

* ** ) e(-kt) T(1200 ** * 2930 *

* ***** K-2930 ** *********** ********* **** T(1200 ** = **** *

* ***** K-2930 ** e(-1800) T(1200 ** = **** K

* ***** K-2930 ********** ****** ** * **** *

* (100 ********** T(1200 ** * **** K

+ *** ** ****** ** *** 2947 **

***** ** ******* *** ******

temperature ** 2947 *

or
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• 232 orders completed

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******** IN WORD *******

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** ****** provide your ******** feedback ***** ** *****

****** ******* me *** **** future work and ***** **** ******* to ***

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**** ** any ***** ****** **** **** ** write on: *************************************

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Tutor has posted answer for $10.00. See answer's preview$10.00