Answered You can buy a ready-made answer or pick a professional tutor to order an original one.
- @
- ANSWER
-
Tutor has posted answer for $10.00. See answer's preview
************ Law ** Cooling ****** **** the **** of change ** *** temperature ** ** ****** ** ************ ** *** difference ******* *** *** *********** *** the ******* *********** *** *** temperature ** *** **************
************
*** of ******* ** **** ** model *** temperature ****** ** an object ** **** *********** ****** ** ** environment ** a different temperature *** law ****** that *****
*
**
***
*********** ** the ****** ** time * * ** the *********** ** *** surrounding *********** ********** *** * ** * ******** ** *************** **** **** *** **** is **** *** **** ** change ** *********** is ************ to the difference ******* *** temperature ** *** ****** *** **** ** *** surrounding ************ ** ***** ** ***
***
******** equation ** ********* **** ** *** *** ** **** ***** *** ************ ******** *** ***** are ***** ****** Separate *** ********* *** ***
***
*******
on
***
side *** *** *** ******* ** *** other side *** ********* can be ** ****** ***** ****************** both sides ***** in the ******** **** **
solve
***
T
**
***
have * useful
equation
****
you
are
******* **** Newton's *** ** ******* remember **** t
**
the
********
The
*****
*******
R * C *** all ********* ** ***** ** **** the *********** ** *** object ** * ***** **** all of the constants must first have numerical ******
- @
- 6 orders completed
- ANSWER
-
Tutor has posted answer for $10.00. See answer's preview
****** **** *** **** ** ****** ** *** temperature ** an ****** ** ************ ** *** ********** ******* its *** *********** and *** ******* *********** (ie the *********** ** its ************* ******** *** ***** * ********* ***** an instantaneous **** ** ****** ** *** ************
See ****** ******
****
*
*********** ** ** ****** at * certain **** ******* K) * *
time **** Ts =
*********** ** *** ************ ******* *** ** =
******** *********** of *** object ******* *** k *
a cooling constant ******** to the ****** ****** ******** Law
**
******* ******* *********** ** * ***
** **** starts at a *********** ** **** * *** *** *********** *********** ** 2930 * ** the ******* constant is * = 000150 *** **** **** *** *********** of the *** of **** be ***** *** ********* ******* *** ****
cools
*** 200 ******* which **** t=200min*60s/1min t * ****
**
***
temperature of *** ****
***** *** ***** **** *** be ***** using *** formula: T(t) * Ts + ***
* ** ) e(-kt) T(1200 ** * 2930 *
* ***** K-2930 ** *********** ********* **** T(1200 ** = **** *
* ***** K-2930 ** e(-1800) T(1200 ** = **** K
* ***** K-2930 ********** ****** ** * **** *
* (100 ********** T(1200 ** * **** K
+ *** ** ****** ** *** 2947 **
***** ** ******* *** ******
temperature ** 2947 *
- @
- 732 orders completed
- ANSWER
-
Tutor has posted answer for $10.00. See answer's preview
******** IN WORD *******
- @
- 17 orders completed
- ANSWER
-
Tutor has posted answer for $10.00. See answer's preview
** ****** provide your ******** feedback ***** ** *****
****** ******* me *** **** future work and ***** **** ******* to ***
**
**** ** any ***** ****** **** **** ** write on: *************************************
*****
***
- @
- ANSWER
-
Tutor has posted answer for $10.00. See answer's preview
**** ****** attached with the **** ********** ** *** *******