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# Pepsi puts 355 ml of pop in a can. How many drops is this?

Here's what I got.

These are classic examples of problems that can be solved by using one or more conversion factors that help you go from one unit to another.

As far as I know, the most common conversion factor used to convert between milliliters to drops and vice versa is

##color(purple)(|bar(ul(color(white)(a/a)color(black)("1 mL " = " 20 drops")color(white)(a/a)|)))##

This tells you that in order to have ##"1 mL"## of soda, you need to have ##20## **drops** of soda. Since you know that a can of soda contains ##"355 mL"## of liquid, you can use this conversion factor to determine how many drops would be needed to get that volume

##355 color(red)(cancel(color(black)("mL soda"))) * "20 drops"/(1color(red)(cancel(color(black)("mL soda")))) = color(green)(|bar(ul(color(white)(a/a)"7100 drops"color(white)(a/a)|)))##

The exact same approach can be used to determine how many bales of hay will be consumed in **one year**. Unless the problem says otherwise, you can usually approximate one year to be equivalent to ##52## **weeks**

##color(purple)(|bar(ul(color(white)(a/a)color(black)("1 year " = " 52 weeks")color(white)(a/a)|)))##

This time, you know that the herd consumes ##14## bales of hay in ##2## **weeks**, which is equivalent to saying that they consume

##1 color(red)(cancel(color(black)("week"))) * "14 bales of hay"/(2color(red)(cancel(color(black)("week")))) = "7 bales of hay"##

in **one week**. Since you need ##52## weeks to get to one year, it follows that the heard will consume ##52## **times** more hay in one year than it does in one week.

##7color(white)(a) "bales of hay"/(1color(red)(cancel(color(black)("week")))) * (52color(red)(cancel(color(black)("weeks"))))/"1 year" = color(green)(|bar(ul(color(white)(a/a)"364 bales of hay/year"color(white)(a/a)|)))##