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Problem 1: A light ray passes from air through glass into water. The index of refraction of the glass is 1. The angle of the refracted ray in the...
Problem 1: A light ray passes from air through glass into water. The index of refraction of the glass is 1.5. The angle of the refracted ray in the water is 43°.Part (a) Draw a qualitative picture (ray diagram) of the situation. Make it clear if it bends towards or away from the normal (perpendicular) at each interface. Label any known angles.
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Part (b) Determine the angle of the incident ray at the air-glass interface. Show your work.
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Problem 2: Light is incident on the boundary between two media at an angle of 25°. The refracted light makes an angle of 45°.Determine the critical angle for light incident on the same boundary. Show your work.
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Problem 3: A swimmer underwater shines a laser pointer at the surface of the water (water/air interface) from under the water.Part (a) Will a person standing at the side of the pool see the laser light if the incident angle is 45°? Show your work.
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Part (b) Will a person standing at the side of the pool see the laser light if the incident angle is 52°? Show your work.
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Part (c) Will a person standing at the side of the pool see the laser light if the incident angle is 57°? Show your work.
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Problem 4: Use ray diagrams and calculations to determine the location of the image of an object in the following situations:Part (a) An object is 15cm from a convex lens of focal length +20cm.
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Part (b) An object is 15cm from a concave lens of focal length -20cm.
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Part (c) Calculate the magnification in part (a) and determine if the image is upright or inverted, real or virtual.
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Part (d) Calculate the magnification in part (b)and determine if the image is upright or inverted, real or virtual.
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Problem 5: You wish to photograph a 1.5m tall person with camera of focal length 0.08m. The image cannot be more than 0.03m tall.Part (a) What is the closest distance the person can stand to the lens to meet these criteria? Show your work.
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Part (b) How far should the image sensor be from the lens for the object distance (nearest distance) calculated in part (a)? Show your work.
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