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Prove Lemma 2.
This is what i have so far but I want to to show that a + e > 0 implies either a = 0 or a > 0. For instance, -3 + 5 > 0 but -3 < 0. Since e > 0. for a + e < 0 to be true, a < -e would have to be true (why?).
Prove Lemma 2.3.10 (2)Let a ERPart 1 a > 0 if and only if a > -8 for all = > 0Suppose a 2 0Let z >0Since a > 0 and = > 0 then a + 8 > 0Then a > -EPart 2 Suppose a > -8 and = > 0)Because & > 0 a can be equal to OSo a 20