# How do you graph #3x-5y=15# using intercepts?

##### 2 Answers

See a solution process below:

#### Explanation:

To find the intercepts, equate one variable to

**y-intercept**

Set

**x-intercept**

Set

Next. we can plot the two points on the grid:

graph{((x-5)^2+(y)^2-0.125)((x)^2+(y+3)^2-0.125)=0 [-20, 20, -10, 10]}

Then, draw a line through the two points:

graph{(3x - 5y -15)((x-5)^2+(y)^2-0.125)((x)^2+(y+3)^2-0.125)=0 [-20, 20, -10, 10]}

Draw a straight line through the intercept points as indicated below.

#### Explanation:

Note that the given equation:

and

Therefore we have the two points:

Plotting these two points on the Cartesian plane and drawing a straight line through them should give a graph that looks like: