Respond to at least two of your classmates’ posts by . Do you agree with how your classmates used the vocabulary? Do the mathematical results seem reasonable? KimotheePart one:d=D(a+1)/24d=500(11+1

Respond to at least two of your classmates’ posts by . Do you agree with how your classmates used the vocabulary? Do the mathematical results seem reasonable? 

Kimothee

Part one:

d=D(a+1)/24

d=500(11+1)/24

d=500(12)/24

d=6000/24

d=200mg

By substituting the known values in the literal equation, I can then solve for the missing variable. First, the age is added to 1, then the multiplication, then division. It's important to add back the identifier (mg) at the end to ensure our answer is accurate.

Part two:

d=D(a+1)/24

24(250)=[250(a+1)/24]24

6000/250=250(a+1)/250

24-1=a+1-1

23 years=a

There's only one solution here, making this a conditional equation. This can be confirmed by substituting the age of 23 back into the formula and solving for the adult does, which equals the original 250mg that was provided.The easiest thing to forget for me is how to simplify fractions as it's with reciprocal multiplication. Then, we divide by the 250 to simplify further. Finally, subtract 1 form both sides. Again, do not forget the label of the answer.

Chelesa

Hi class,

I got number 15. Part a says adult dose 500mg amoxicillin; 3 year old child. Part b says 250mg adult, 25 child. I used d=D(a+1) to figure this out.

                        24

a.

d=500(3+1)

     24

3+1=4

4x500=2000

2000/24=83.33

d=83.33mg

In this formula I  had to solve for variable d. First, I had to substitute my variables with integers I was given. D=500, a=3. I started in the parentheses to get 4. Then I multiplied 4 by 500. Next I divided the product (2000) by 24 to create the final answer 83.33. This is a conditional equation because we only get one answer after finishing the formula. 

b.

25=250(a+1)

      24

25x24=600

600=250(a+1)

600/250=2.4

2.4=(a+1)

2.4-1=1,4

a=1.4 years

In this literal equation I also substituted the variables with my integers. d=25, D=250. In this equation I multiplied both sides by 24. I got my product of 600. Next I divided both sides by 250 to get rid of it from both sides of the equation. That left me with 2.4=a+1. I subtracted 1 from both sides to conclude that 1.4=a.