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Show by contradiction that "Let x be a natural number. If x is multiple of 3, then x^2 is multiple of 9.
Show by contradiction that “Let x be a natural number. If x is multiple of 3, then x^2 is multiple of 9.”
Solution:Let us assume x^2 is not multiple of 9.i.e. x^2 ^2 where k is any natural number.Or we can write it asXXWhich says x is not multiple of 3.but it is given x is multiple of 3.Hence...