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solve Sin(3theta)= -sqrt(2)/2 for all solutions of theta in the interval [0, 2pi).
- solve Sin(3theta)=-sqrt(2)/2 for all solutions of theta in the interval [0, 2pi).
Please Explain/ stepsThis is general solutionPut n = 0 and m = 0So x = 5pi / 12 , 7pi / 12For n = 1 and m = 1X = 13pi / 12 , 15pi / 12For n =2 and m =2 answer is outside the range soanswers areSo x = 5pi / 12 ,...