Statistic Quiz Due in 30 mins Module 4

Question 1

Not yet answered

Marked out of 1.00

Flag question

Question text

Assume that you plan to use a significance level of α = 0.05 to test the claim that p1 = p2. Use the given sample sizes and numbers of successes to find the pooled estimate p. Round your answer to the nearest thousandth.n1 = 100               n2 = 100               x1 = 53                  x2 = 48

Select one:

a. 0.9901

b. 0.5050

c. 1.9802

d. 1.0100

Question 2

Not yet answered

Marked out of 1.00

Flag question

Question text

Construct the indicated confidence interval for the difference between population proportions p1 - p2. Assume that the samples are independent and that they have been randomly selected.  In a random sample of 300 women, 59% favored stricter gun control legislation. In a random sample of 200 men, 38% favored stricter gun control legislation. Construct a 98% confidence interval for the difference between the population proportions p1 - p2.

Select one:

a. 0.2000 < p1 - p2 < 0.2200

b. 0.1900 < p1 - p2 < 0.2300

c. -2.1164 < p1 - p2 < 2.5363

d. 0.1064 < p1 - p2 < 0.3136

Question 3

Not yet answered

Marked out of 1.00

Flag question

Question text

Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal.   Independent samples from two different populations yield the following data. x-bar1 = 763, x-bar2 = 585, s1 = 38, s2 = 31. The sample size is 478 for both samples. Find the 80% confidence interval for μ1 - μ2.

Select one:

a. 178.2000 < μ1 - μ2 < 177.8000

b. 941.0000 < μ1 - μ2 < 177.8000

c. 176.7167 < μ1 - μ2 < 180.8144

d. 175.1856 < μ1 - μ2 < 180.8144

Question 4

Not yet answered

Marked out of 1.00

Flag question

Question text

Assume that you plan to use a significance level of α = 0.05 to test the claim that p1 = p2. Use the given sample sizes and numbers of successes to find the P-value for the hypothesis test.n1 = 100                  n2 = 100                  x1 = 12                    x2 = 18

Select one:

a. 0.0250

b. 0.1174

c. -1.1882

d. 1.9600

Question 5

Not yet answered

Marked out of 1.00

Flag question

Question text

A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B:-2.90 hrs < μ1 - μ2 < 7.50 hrsWhat does the confidence interval suggest about the population means?

Select one:

a. The confidence interval includes only positive values, which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

b. The confidence interval includes only negative values, which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

c. The confidence interval includes 0 which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

d. The confidence interval includes 0 which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

Question 6

Not yet answered

Marked out of 1.00

Flag question

Question text

When performing a hypothesis test for the ratio of two population variances, the upper critical F value is denoted FR. The lower critical F value, FLFind the critical value FL a hypothesis test based on the following values:n1 = 25, n2 = 16, α = 0.01

Select one:

a. 6.5430

b. 0.3081

c. 0.3462

d. 0.3555

Question 7

Not yet answered

Marked out of 1.00

Flag question

Question text

Consider the set of differences, denoted with d, between two dependent sets: 8, 11, 12, 7, 3, 15. Find the sample standard deviation sd .

Select one:

a. 4.2269

b. 2.0560

c. 9.3333

d. 17.8667

Question 8

Not yet answered

Marked out of 1.00

Flag question

Question text

Determine the decision criterion for rejecting the null hypothesis in the given hypothesis test; i.e., describe the values of the test statistic that would result in rejection of the null hypothesis.  We wish to compare the means of two populations using paired observations. Suppose that d-bar = 5.11, sd = 1.7, and n = 13, and that you wish to test the following hypothesis at the 10% level of significance:               H0: μd = 0 against H1: μd > 0.What decision rule would you use?

Select one:

a. Reject H0 if test statistic is greater than -1.3526.

b. Reject H0 if test statistic is less than 1.3562.

c. Reject H0 if test statistic is greater than 1.3526.

d. Reject H0 if test statistic is greater than -1.3526 and less than 1.3526.

Question 9

Not yet answered

Marked out of 1.00

Flag question

Question text

The two data sets are dependent. Find d-bar .A     44     41     36     38     26B     25     23     20     25     22

Select one:

a. 6.0415

b. -35

c. -70

d. -14

Question 10

Not yet answered

Marked out of 1.00

Flag question

Question text

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd = 0. Compute the value of the t test statistic. x   58     61     50     55    58    57    63    65y   56     57     56     55    59    62    63    64

Select one:

a. t = 0.690

b. t = 0.0654

c. t = -2.3646

d. t = 0.5233