Suppose a 375-mL sample of neon gas at 78°C is cooled to 22°C at constant pressure. What will the new volume be of the neon sample?

We can find the effect of temperature on the Volume using the equation.

##V_1 ## / ##T_1## = ##V_2## / ##T_2##

##V_1## = 375 mL , ##T_1## = 273 + 78 = 351 K

##V_2## = ? , ##T_2##= 273 + 22 = 295 K

375 mL / 351 K = ##V_2## / 295K

375 mL x 295 K / 351 K = ##V_2##

##V_2## = 110625 L K/ 351 K = 315.17 L