Suppose a simple random sample of size n =200 is obtained from a population whose size is N = 20,000 and whose population proportion with a specied

I need help solving problem B on the Calculator TI84

Suppose a simple random sample of size n =200 is obtained from a population whose size is N = 20,000 and whose population proportion with a specified characteristic is p = 0.8. B. Approximately normal because n 5 0.05N and np(1 — p) < 10.C. Not normal because n $0.05N and np('l — p) < 10.D. Not normal because n $0.05N and np(1 — p)? 10. Determine the mean of the sampling distribution of 6. p. = 0.8 (Round to one decimal place as needed.)p Determine the standard deviation of the sampling distribution of 6. as = 0.028284 (Round to six decimal places as needed.) (b) What is the probability of obtaining X: 164 or more individuals with the characteristic? That is, what is P52 0.82)? P(p2 0.82) = (Round to four decimal places as needed.)