Suppose the acceleration of a moving object is given by a(t)=4t+6 in m/s^2.

Suppose the acceleration of a moving object is given by a(t)=4t+6 in m/s^2. If the object has an initial velocity of -8m/s, find the total distance traveled by the object during the time interval 0 < t < 2

Given that the acceleration a ( t )=4 t+6v ∫ dV = ( 4 t+ 6 ) dt−8 4 2V −(−8 ) = t +6 t22 V =2 t +6 t−8Integrating velocity to find displacementt 2 ∫ dV =∫ ( 2 t2 +6 t−8 ) dt...