Take -Na homogenously distributed in water , with an initial specific activity of ! Ci/} . The half life is 15 his so to simplify just...

Question is above. Please solve it step by step.

Take 24Na homogenously distributed in water, with an initial specific activity of 1

μCi/g. The half life is 15 hrs so to simplify just average over the first 10 minutes of

measurement and assume that activity remains constant over the full measurement time.

Assume a very large volume

3 . Take -"Na homogenously distributed in water , with an initial specific activity of !"Ci/} . The half life is 15 his so to simplify just average over the first 10 minutes ofmeasurement and assume that activity remains constant over the full measurement time .Assume a very large volume and ( a ) Find the close at the center due to each of the betasand gammas listed for* * Na in appendix C , and the total close . Do not use the equilibriumclose constants .( b ) Repeat ( a ) using the equilibrium dose constants .( C ) Now for the volume you have in problem 2 , find the close in the center . Pay attentionto absorbed fractions . You can approximate the appropriate Men .ans .( a and b )B: 197 mead$ 1 : 486 mrad* 2: 977 mad1 3 : 1 meadtotal 1. 661 rad( C )B: 197 mrad$ 1 : 237 mradY 2: 404 mrad1 3: 0. 4 meadtotal 838 mrad