The Center for Disease Control has reported that 47% (p=0.47 p=0.47) of U. adults (over the age of 30) have periodontal disease. We plan to take a...

The Center for Disease Control has reported that 47% (p=0.47

p=0.47) of U.S. adults (over the age of 30) have periodontal disease. 

We plan to take a random sample of 250 adults.

The sampling distribution of p

¯

p¯  is:

Select one:

a. normal because np≥5

np≥5   and  n(1−p)≥5

n(1−p)≥5

b. normal because np≤5

np≤5   and  n(1−p)≤5

n(1−p)≤5

c. not normal because the sample size is too small

d. normal because np≤5

The standard error (SE) of  p

¯

p¯  is

Select one:

a. 0.032

b. 0.006

c. 0.025

d. 0.001

What is the probability that a random sample of 250 U.S. adults will provide a sample proportion (p

¯

p¯) that is within 0.03 of the population proportion (p

p)? 

Select one:

a. 57%

b. 23%

c. 65.15%

d. 77%

What is the probability that a random sample of 250 U.S. adults will provide a sample proportion (p

¯

p¯) that is within 0.09 of the population proportion (p

p)?

Select one:

a. 96.555%

b. 0.436%

c. 99.508%

d. 0.218%

Say, you took a random sample of 250 U.S. adults, and found out that the sample proportion (p

¯

p¯) for this sample to be 0.58 (or 58%). In light of your observation from the PRECEDING question, 

Select one:

a. This is not considered a strange finding because a sample proportion of 58% is quite likely