The easy way to figure this out is to let x = 0. Then y = f (0 + c) = f (0), so the value of f (x) at c is shifted to be the value of f at 0. Thus...

The easy way to figure this out is to let x = 0. Then y = f (0 + c) = f (0), so the value of f (x) at c is shifted to be the value of f at 0. Thus the graph is shifted a distance c to the left . Similarly, the graph of y = f (x - c) is that of y = f (x) shifted a distance c to the brackets causes a right. Inside the brackets? In other words, how are the graphs of y = f (x + c) and y = f (x - c) related to the graph y = f (x)?