The latent heat of vaporization of water is 2260 J/g. How many grams of water at 100°C can be converted to steam by 226,000 J of energy?

The answer is: ##m=100g##.

To answer to this question it is sufficient to use this equation:

##Q=Lm##

where

##Q## is the amount of heat needed to convert water in steam;

##L## is the of vaporization of water;

##m## is the mass of the water.

So:

##m=Q/L=(226000J)/(2260J/g)=100g##.