The perimeter of a basketball court is 280 ft. The length is 42 ft longer than the width. What are the dimensions of the court?

The length is 91 ft. and the width is 49

We're going to solve this problem using system of equations. We will use variable ##l## for length and ##w## for width. Also it's fairly safe to assume that the basketball court is rectangular.

The formula for perimeter of a rectangle is ##2l+2w=p##. We know that the perimeter is 280 so our first equation will be ##2l+2w=280##.

Our second equation will come from "The length is 42 ft longer than the width". If we turn that sentence into a formula we can get ##l=42+w##.

Now we can plug in our second equation into our first for ##l## ##2(42+w)+2w=280##

Now we may simplify and solve for ##w##. ##84+2w+2w=280 84+4w=280 4w=196 w = 49##

Now we plug in our width into our second equation ##l=42+49## ##l=91##

So our final answer will be the length is 91 ft. and the width is 49.