Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.

# The rate of effusion for ##H_2O## vs. ##H_2S## is______?

The rate of effusion for water and hydrogen sulfide is **1.375**.

To determine the rate of effusion for a gas, you can use **Graham's Law**

##"rate" prop 1/sqrt(M_M)##, where

##M_M## - the molar mass of the gas.

So, the rate of effusion of a gas is proportional to ##1/sqrt(M_M)##. This tells you that the **heavier the gas molecules are**, i.e. the bigger their molar mass is, the **slower** the effusion rate.

In your case, you have to determine the ratio between the effusion rate of water and the ffusion rate of hydrogen sulfide. Using Graham's Law, you can write

##"ratio" = r_(H_2O)/r_(H_2S) = 1/sqrt(M_("M"H_2O)) * sqrt(M_("M"H_2S)##

##r_(H_2O)/r_(H_2S) = sqrt(M_("M"H_2S))/sqrt(M_("M"H_2O))##

This means that you get

##r_(H_2O)/r_(H_2S) = sqrt(34.08cancel("g/mol"))/sqrt(18.02cancel("g/mol")) = sqrt(34.08/18.02) = color(green)(1.375)##

In other words, water has a faster effusion rate than hydrogen sulfide.