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The time to failure (in hours) of a bearing is satisfactorily modeled as a Weibull random variable with shape parameter beta =2 and scale parameter...

The time to failure (in hours) of a bearing is satisfactorily modeled as a Weibull random variable with shape parameter beta =2 and scale parameter theta = 5000 hours.a. Determine the mean time until failure for these bearings.b. Determine the probability that a bearing lasts at least 6000 hours.

The time to failure (in hours) of a bearing is satisfactorily modeled as a Weibull random variable with shape parameter beta =1/2 and scale parameter theta = 5000 hours.a. Determine the mean time...
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