The volume of fuel in a tank changes at a rate given by the equation 0V'\left(t\right)=\frac{4t}{\sqrt[3]{t^2+3}},\:t\ge0 at t= \sqrt6 hours the tank...

The volume of fuel in a tank changes at a rate given by the equation

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 at t=​ hours the tank holds 9.5 gallons. What is the volume of fuel in the tank after 7

hours? Round answer to one decimal place.

Not too sure where to start. Please explain as much as possible. Thanks