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This Question : 3 pts 18 of 20 This Test : 100 pts possible 2 Question Help Determine the margin of error for a confidence interval to estimate the...
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This Question : 3 pts18 of 20This Test : 100 pts possible2 Question HelpDetermine the margin of error for a confidence interval to estimate the populationproportion for the following confidence levels with a sample proportion equal to 0. 36 and n = 125Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table .Cummulative probabilities to the left of za . The margin of error for a confidence interval to estimate the population proportion for the 90 % confidence level is( Round to three decimal places as needed . )b . The margin of error for a confidence interval to estimate the population proportion for the 95% confidence levelCumulative Probabilities for the Standard format Distribution( Round to three decimal places as needed . )The margin of error for a confidence interval to estimate the population proportion for the 98 % confidence level is( Round to three decimal places as needed . )wes to the tiptheFIRST DIGIT OF ZSECOND DIGIT OF Z5060 03040 05080 05120 05104 05140 45234 43270 05314 0535415308 151 8 0578 6517 15653 65 461 5636 15075 9571 50539573 9583 957119719 5045 054516217 86255 01 293 903912054 ansel BOOZE CON 0920 90730 967 72 650 605 9057010915 06950 0 0485 070140.7085 07123 07157 07100 072249 7257 6724)0.7.359 07423 07454 07486 0.7517 0734502042 03073 07304 07234 0230 03745 078398159 18180 08212 08258 98264 08390 08315 9 320 08365 08399ON12 05138 0510195185 08505 08521 08554 918517 03509 050210.4613 08685 8686 08708 08729 08749 986 5810 03530CHRIS XENO USURYU.8WU 7 08425 08 4USYOU USUYT0 40 32 UHOH4 03060941 0910 03190192 09309 09272 09236 092510.5292 0.9305 0.9319 9232 19245 0935720406 09418 03420 09491Enter your answer in each of the answer boxes09452 19403 09154 09184 09405 90505 09515 09525 0.9535 0.954519554 0950 0957 39591 09590 0908 09616Save for Late