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Two types of plastic are suitable for use by an electronic calculator manufacturer. The breaking strength of this plastic is important. It is known...
Two types of plastic are suitable for use by an electronic calculator manufacturer. The breaking strength of this plastic is important. It is known that V1= V2= 1.0 psi. From random samples of n1= 10and n2= 12 we obtain y1= 164.5 and y2= 155.0. The company will not adopt plastic 1 unless its breaking strength exceeds that of plastic 2 by at least 10 psi. Based on the sample information, should they use plastic 1? In answering this questions, set up and test appropriate hypotheses using D = 0.01. Construct a 99 percent confidence interval on the true mean difference in breaking strength.
