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UDP and TCP use 1s complement for their checksums. Suppose you have the following three 8-bit bytes: 01010101, 01110000, 01001100. What is the 1s
UDP and TCP use 1s complement for their checksums. Suppose you have the following three 8-bit bytes: 01010101, 01110000, 01001100. What is the 1s complement of the sum of these 8-bit bytes?(Note that although UDP and TCP use 16-bit words in computing the checksum, for this problem you are being asked to consider 8-bit sums.) Show all work. Why is it that UDP takes the 1s complement of the sum; that is.Why not just use the sum? With the 1s complement schema, how does the receiver detect errors? Is it possible that a 1-bit error will go undetected? How about 2-bit error?------------------------>Please explain IN DEPTH ALL PARTS OF QUESTION and SHOW ALL ADDITION OF THE THREE BINARY 8 BIT BYTES along with the carry over of ones in the addition of the problem. I have the answer that wikipedia posted, but need a different one, that has explanation!
