We will find the 95% confidence interval, which will be as follow you will take that sample size of 30 with the mean of 15.854, a standard deviation...

We will find the  95% confidence interval, which will be as follow you will take that sample size of 30 with the mean of 15.854, a standard deviation of 0.661, and a desired confidence level of 95%, the corresponding confidence interval would be ± 0.24. That is to say that you can be 95% certain that the true population mean falls within the range of 15.62 to 16.09 .

x-bar +/- ợ/√n

Mean= x .854

Sample Size:

Sample Observed Standard Deviation= ợ= 0.66138

Level-95% Confidence interval is as follow:

15.824 +/-1.96*0.66138/√30

Confidence .24

Range for the true population mean= 15.62 to 16.09

The Null Hypothesis: mean weigh of soda ounces

Alternative Hypothesis: mean weigh of the soda bottle< 16 ounces

Mean = bar = 15.854

Sample Size

Standard deviation = ợ  = 66138

Z= (x – x bar) / (ợ / √n)

Z= ( 16.00- 15.854) / (66138 /√30)

Z=

Now the probability Z< =

Probability of x < 16 =

Can you help me finish the last part, having trouble. I need this as soon as possible