What are the dimensions of a soccer field if the perimeter is 300 years and the length is 50 yards longer than the width?

width = 50 and length = 100

For simplicity, we will use the letters W for width, L for length and P for perimeter.

For a rectangular field ##P = 2 * (L + W)## So we have ##2 * (L + W) = 300## or ##L + W = 150##

We are told that ##L = W + 50## So ##L + W = 150## can be re-written as ##(W+50) + W = 150## which can be simplified: ##2W + 50 = 150## ##2W = 100## ##W = 50##

And since ##L = W +50## ##L = 50 + 50 = 100##

Therefore the width is 50 (yards) and the length is 100 (yards).