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QUESTION

# What are the polar coordinates of (1, sqrt3)?

I found: (2,pi/3)

Consider the following diagram:

We can see that the relationships between rectangular and are: r=sqrt(x^2+y^2) theta=arctan(y/x) and: x=rcos(theta) y=rsin(theta)

In your case: x=1 y=sqrt(3) use them into: r=sqrt(x^2+y^2) theta=arctan(y/x) to get: r=sqrt(1+3)=sqrt(4)=2 theta=arctan(sqrt(3))=60^@=pi/3"rad"