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QUESTION
What is the antiderivative of ##sin^2(x)##?
##= 1/2[x - 1/2sin2x] + C##
We're going to use the trig identity
##cos2theta = 1 -2sin^2theta##
##implies sin^2x = 1/2(1 - cos2x)##
So ##int sin^2xdx = 1/2int(1-cos2x)dx##
##= 1/2[x - 1/2sin2x] + C##
