Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.

QUESTION

# What is the decay equation of cesium 137?

""_ 55^137Cs -> ""_ 56^137Ba + ""_"-1"^0beta

Cesium-137 has an of 55, so is written as

""_55^137Cs.

It is also a beta-emitter, which means it undergoes beta-decay by a neutron decaying into a proton, releasing an electron.

Protons and neutrons have the same mass, so the doesn't change. The atomic number increases by one, because one more proton is formed.

Because the atomic number changes, this is a new element, number 56, barium, or

""_56^137Ba

In the form of an equation, this is written as

""_ 55^137Cs -> ""_ 56^137Ba + ""_"-1"^0beta

This video shows a sample of Cs-137 being tested by a hand-held detector.