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QUESTION
What is the derivative of ##y=ln(sec(x)+tan(x))##?
Answer: ##y'=sec(x)##
Full explanation:
Suppose, ##y=ln(f(x))##
Using , ##y'=1/f(x)*f'(x)##
Similarly, if we follow for the problem, then
##y'=1/(sec(x)+tan(x))*(sec(x)+tan(x))'##
##y'=1/(sec(x)+tan(x))*(sec(x)tan(x)+sec^2(x)) ##
##y'=1/(sec(x)+tan(x))*sec(x)(sec(x)+tan(x))##
##y'=sec(x)##
