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# What is the empirical formula and empirical formula mass for the following compound: C3H6O3?

The empirical formula is ##"CH"_2"O"##. The empirical formula mass is ##"30.026##.

An empirical formula represents the simplest whole number ratio of in a compound.

The given formula, ##"C"_3"H"_6"O"_3"##, is not an empirical formula because the subscripts can be divided by the whole number ##3## to simplify the formula to ##"CH"_2"O"##, which is the empirical formula.

Determine the empirical formula mass by multiplying each element's subscript by its atomic weight on and adding them together.

##"Empirical formula mass"####=####(1xx12.0107)+(2xx1.00794)+(1xx15.999)=30.026##