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# What is the formula weight of silver chromate ##(Ag_2CrO_4)## in amu?

The formula weight for ##"Ag"_2"CrO"_4"## is ##"331.728 u"##.

In order to determine the formula weight of a compound, multiply the atomic weight on of each element by its subscript and add the results.

**Compound:** silver chromate**Formula Unit:** ##"Ag"_2"CrO"_4"##

##(2xx"107.868 u Ag")+(1xx"51.9961 u Cr")+(4xx"15.999 u O")="331.728 u"##