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What is the limit as x approaches infinity of ##sin(x)##?
As x approaches infinity, the y value oscillates between 1 and -1; so this limit does not exist.
The answer is it DNE.
One good rule to have while solving these problems is that generally, if there is no x in the denominator at all , then the limit does not exist.
Example:
- ##lim_(x->oo)sinx=DNE##
- ##lim_(x->oo)(sinx)/(x)=0## (Squeeze Theorum)
This is the same question as below: