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QUESTION

# What is the magnetic quantum number of the 19th electron of Calcium?

0

of Calcium "Ca" is 20.

We know that there are four which can be assigned to "describe" any electron in an atom. Each electron has a unique set of these four quantum numbers.

n = principal quantum number, which defines the energy level of the electron.

l = azimuthal (angular) quantum number defining the energy sub-level. Its values range from 0 " to " (n-1); 0=s, 1=p, 2=d, 3=f

m(l) = magnetic quantum number indicating orbital within a sublevel. Range from -l" through "0" to "+l

m(s) = spin quantum number. It identifies an electron within an orbital and can have either of the two values +1/2 and -1/2

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The electronic configuration of calcium is: 1"s"^2; 2"s"^2, 2"p"^6; 3"s"^2, 3"p"^6; 4"s"^2 or ["Ar"] 4"s"^2

it is evident that the 19th electron goes to 4"s" energy level. As such for it n=4, l=0 We know that for l=0, m(l)=0 only. Hence magnetic quantum number m(l) of 19th electron of calcium is =0

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