What is the net centripetal force needed to keep the car from skidding sideways? Answer in units of N. 010 (part 2 of 5) 10.0 points Were there no

For questions 14-16, what equations would you use??

What is the net centripetal force needed tokeep the car from skidding sideways?Answer in units of N. 010 (part 2 of 5) 10.0 pointsWere there no friction between the car’s tiresand the road, what centripetal force could beprovided just by the banking of the road?Answer in units of N. 011 (part 3 of 5) 10.0 pointsNow suppose the friction force is sufficient tokeep the car from skidding. Calculate themagnitude of the normal force exerted on thecar by the road’s surface. Hint: Check thecorrectness of your answer to the first questionbefore proceeding with this and the followingquestions.Answer in units of N. 012 (part 4 of 5) 10.0 pointsCalculate the magnitude of the friction force.Answer in units of N. 013 (part 5 of 5) 10.0 pointsCalculate the lowest possible value of thestatic friction coefficient Ms that would pre—vent the car from skidding. 014 (part 1 of3) 10.0 pointsA 8 g rock on a string is whirled fast enough(in a clockwise direction) to move in a verticalcircle as shown. The rock has only enoughvelocity at the top of the loop to keep a verysmall (negligible) tension in the string. The angle 312° is measured from the verti-cal axis when the rock is at its lowest position(i.e., measured from the negative y axis in acounter-clockwise direction). What is the magnitude of the centripetal acceleration when 6 = 312° ?Answer in units of m/s2. 015 (part 2 of 3) 10.0 pointsWhat is the magnitude of the total accelera—tion when 9 = 312° ?Answer in units of m/s2. 016 (part 3 of 3) 10.0 pointsWhat angle does the total acceleration makewith the string when 3 2 312° ?Answer in units of°.