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# What is the orbital hybridization in pf5?

the hybridization of ##PF_5## is ## sp^3d## .

In ##PF_5## , the valence electrons of phosphorus are 5. and we take the oxidation state of halogens as 1.

So, for one F , electron is 1 and for ##F_5## the no. of electrons is 5.

therefore, (from phosphorus and fluorine)

**5-5=0 electrons = 0 lone pairs.**

there are 5 sigma bonds in this compound.

So, 5 sigma bonds + 0 lone pairs = 5. ##->## ** ##sp^3d## **

hence , the hybridization of this compound is ##sp^3d## .

Note:-

2 has sp hybridization. 3 has ##sp^2## hybridization. 4 has ##sp^3## hybridization. 5 has ##sp^3d## hybridization. 6 has ##sp^3d^2##