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What is the orbital hybridization in pf5?
the hybridization of ##PF_5## is ## sp^3d## .
In ##PF_5## , the valence electrons of phosphorus are 5. and we take the oxidation state of halogens as 1.
So, for one F , electron is 1 and for ##F_5## the no. of electrons is 5.
therefore, (from phosphorus and fluorine)
5-5=0 electrons = 0 lone pairs.
there are 5 sigma bonds in this compound.
So, 5 sigma bonds + 0 lone pairs = 5. ##->## ##sp^3d##
hence , the hybridization of this compound is ##sp^3d## .
Note:-
2 has sp hybridization. 3 has ##sp^2## hybridization. 4 has ##sp^3## hybridization. 5 has ##sp^3d## hybridization. 6 has ##sp^3d^2##