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QUESTION

# What is the orbital hybridization in pf5?

the hybridization of PF_5 is  sp^3d .

In PF_5 , the valence electrons of phosphorus are 5. and we take the oxidation state of halogens as 1.

So, for one F , electron is 1 and for F_5 the no. of electrons is 5.

therefore, (from phosphorus and fluorine)

5-5=0 electrons = 0 lone pairs.

there are 5 sigma bonds in this compound.

So, 5 sigma bonds + 0 lone pairs = 5. -> sp^3d

hence , the hybridization of this compound is sp^3d .

Note:-

2 has sp hybridization. 3 has sp^2 hybridization. 4 has sp^3 hybridization. 5 has sp^3d hybridization. 6 has sp^3d^2