Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.

QUESTION

# What is the oxidation number for Sulfur in the compound Na2SO4?

The oxidation number of sulfur is +6

Sodium sulfate(VI) is Na_2SO_4

It contains 2 Na^+ for every SO_4^(2-) ions.

Oxygen has oxidation number -2 in the sulfate(VI) ion.

The on the ion is equal to the arithmetic sum of the .

So oxygen contributes 4 x -2 = -8

Since the net charge is -2 the sulfur must contribute +6 since 6 + (-8) = -2

So the oxidation number is +6 hence the name sulfate(VI).

LEARN MORE EFFECTIVELY AND GET BETTER GRADES!