Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.

QUESTION

# What is the percentage of cation in ammonium dichromate ?

The formula unit for ammonium dichromate is "(NH"_4)_2"Cr"_2"O"_7", and has a molar mass of 252.07 "g/mol".

The ammonium ion, "NH"_4^+", is the cation, and its molar mass is 18.039 "g/mol". Since there are two moles of ammonium cations in one mole of ammonium dichromate, we multiply 18.039 "g/mol"xx2 , which is equal to 36.078 "g/mol".

To find the percentage of ammonium cations in ammonium dichromate, divide the total mass of the ammonium cations by the molar mass of ammonium dichromate and multiply times 100.

"%NH"_4^+=(36.078 "g/mol")/(252.07 "g/mol")xx100=14.313%