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What is the perimeter of a right triangle with a leg of 10 units and a hypotenuse of square root of 127 units?
The perimeter is ##10+3\sqrt{3}+\sqrt{127}## units.
The hypoteneuse squared is 127. One leg squared is 100. The other leg squared must be the difference, ##127-100=27##. Thus the length of that leg is ##\sqrt{27}=3\sqrt{3}##.