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QUESTION
What is the perimeter of a triangle with vertices located at ##(1, 3), (2,6),## and ##(0, 4),## rounded to the nearest hundredth?
Perimeter of the triangle is ##7.40## unit
Side##AB=sqrt((1-2)^2+(3-6)^2)=sqrt10=3.16## Side##BC=sqrt((2-0)^2+(6-4)^2)=sqrt8=2.83## Side##CA=sqrt((0-1)^2+(4-3)^2)=sqrt2=1.41## Perimeter of the triangle is ##3.16+2.83+1.41 =7.40##unit[Ans]
