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# What is the shape of SF4 (including bond angles)?

Within the context of **VSEPR theory**, you can count electrons to determine the **electron geometry** ("parent" geometry).

**Sulfur**: **6** valence electrons**Fluorine**: **7x4** valence electrons**Total**: **34** valence electrons

You can put sulfur in the middle because fluorine tends to make single bonds. Therefore, you can put **6x4** on each fluorine, **2x4** to account for four single bonds, and **2** for the last **2** valence electrons available.

As a result, you have **5** electron groups, so the electron geometry would be **trigonal bipyramidal**. With one lone pair of valence electrons, you get a **seesaw** molecular geometry.

Note though that the structure is distorted a bit due to the repulsive forces of the lone pair of electrons you see (not bonded).

So, that bends the axial fluorines together a bit. Normally the axial ##"F"-"S"-"F"## angle would be ##180^@## (because of course they are exactly opposite/antiparallel to each other), but it becomes ##173.1^@##, and normally the equatorial ##"F"-"S"-"F"## angles are ##120^@## (because the horizontal plane would distribute three connected atoms evenly over ##360^@##), but they become ##101.6^@##.