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What is the simplified radical form of ##sqrt(96)##?
##=color(blue)(4sqrt6##
Simplifying this expression involves prime factorisation of ##96##
##96= 2*2*2*2*2*3## (##2 and 3## are the prime factors of ##96##)
So ##sqrt(96)=sqrt(2*2*2*2*2*3)##
##=sqrt(2^2 *2^2 *2*3)##
##=2*2sqrt6##
##=color(blue)(4sqrt6##