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# While solving an equation for wavelength if you are given MHz as the frequency what do you multiply it by to transfer it to s^-1 or hz?

You need to multiply it by ##10^6##, or divide it by ##10^(-6)##.

You need to become familiar with **metric prefixes**, which are used to indicate either **multiples** of a basic unit, which in your case is Hertz, or **fractions of a basic unit.

You are given a frequency expressed in **megahertz**, or ##"MHz"##. As you can see in the above table, the mega- prefix is used to designate a **multiple** of the basic unit.

More specifically, mega- means **one million times more** than the basic unit. This means that if you take one hertz and multiply it by one million, or ##10^6##, you will get **one megahertz**.

Likewise, to go from megahertz back to hertz, you would have to reverse the process, i.e .**divide** by one million.

This means that if you divide one megahertz by ##10^6##, you get one hertz.

##"1 Hz" = "1 MHz"/10^6 = 10^(-6)"MHz"##

Therefore, to convert ##"99.5 MHz"## to ##"Hz"##, you would write

##99.5color(red)(cancel(color(black)("MHz"))) * "1 Hz"/(10^(-6)color(red)(cancel(color(black)("MHz")))) = 99.5 * 10^(6)"Hz" = 9.95 * 10^(7)"Hz"##

Alternatively, you can use the conversion factor

##"1 MHz" = 10^(6) * 1"Hz" = 10^(6)"Hz"##

to get the same result

##99.5color(red)(cancel(color(black)("MHz"))) * (10^6"Hz")/(1color(red)(cancel(color(black)("MHz")))) = 9.95 * 10^(7)"Hz"##