Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.

QUESTION

Why does (or "do"?) Barium Oxide + Sulfuric Acid yield Ozone?

Here's what I got.

Ok, now this is a very interesting question.

First thing first, the reaction involves barium peroxide, ##"BaO"_2##, not barium oxide, which is ##"BaO"##.

Now, as far as I know, this reaction is used to produce hydrogen peroxide, ##"H"_2"O"_2##.

If you plan on using dilute sulfuric acid, you should use barium peroxide octahydrate, ##"BaO"_2 * 8"H"_2"O"##. The reason behind this is that barium sulfate, ##"BaSO"_4##, which is an insoluble ionic compound, forms on the surface of the peroxide, essentially halting the reaction.

Also, the reaction is performed with an ice-cold acid solution because the low temperature slows down the of hydrogen peroxide to water and oxygen gas.

##2"H"_2"O"_text(2(aq]) -> 2"H"_2"O"_text((aq]) + "O"_text(2(g]) uarr##

The balanced chemical equation for when this reaction (I'll use anhydrous barium peroxide for the sake of simplicity) is performed at low temperature looks like this

##"BaO"_text(2(s]) + "H"_2"SO"_text(4(aq]) -> "BaSO"_text(4(s]) darr + "H"_2"O"_text(2(aq])##

At room temperature and catalyzed by potassium iodide, ##"KI"##, this reaction should proceed like this

##2"BaO"_text(2(s]) + 2"H"_2"SO"_text(4(aq]) stackrel(color(red)("KI")color(white)(aa))(->) 2"BaSO"_text(4(s])## ##darr + 2"H"_2"O"_text((aq]) + "O"_text(2(g]) uarr##

So my guess is that this reaction will produce ozone as a side product, maybe depending on a combination of catalyst, reaction temperature, and concentration of the acid.

I was able to find a YouTube video on this supposed reaction - the narration and the subtitles are in Russian, so that will not be very helpful to students who don't speak it.

Show more
LEARN MORE EFFECTIVELY AND GET BETTER GRADES!
Ask a Question