QUESTION

divide 29 into two parts so that the sum of the squares of the parts is 425.Find the value of each part?

\$10.00

***** ** *** you **** ********* *** **** statement into * ************ statement ** order ** solve those **** ** ******** ** let ** ******* *** statement "divide 29 **** *** ***** so that *** *** ** *** ******* ** *** ***** ** ******* the ***** ** **** part" ***************

******

** **** *** ***** ****** **** means 29 ** ********* **** *** parts (let them be x *** y) ** that ******* ****

***

sum ** *** ******* ** *** ***** ** 425--> this ***** **** *** square ** * ** ***** to *** ****** of * *** ****** ** 425 ** *** + y^2 ***** *********** Now

we

****

***

********* *** *** ******** ***** are: (1) *** * ***

*****

(2) x+y=29 *** ** *******

****

********* simultaneously

******

******* ******* (29-y)^2+y^2=425 ******************** 2y^2-58y+416=0 *********

by

******** both ****

**

***

********

**

***

************* **** ******* *************** ********* * *** be 13 *** ***

since

** *** x=29-y

****

*

***

be ** and ** ************** ** ***

*****

** y so our ***** answers *** 13 *** 16 ********** ********* 13^2 + **** * ****

*******

**

or