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You have a parallel plate capacitor (plate area A andseparation d) initially filled with a dielectric with a permittivity e = (er)*(e0) (er gt; 1).
You have a parallel plate capacitor (plate area A andseparation d) initially filled with a dielectric with a permittivity e = (er)*(e0) (er > 1). You havecharged up the plates (Q on top plate and -Q on bottom plate). If you pull out the dielectric,without disturbing the charge on the plates:a) Will the electric field inside change? If yes, byhow much?b) Will the stored energy in the capacitor change?If yes, by how much?c) If the original stored energy was 2x10-5 J and the work required to pull out the dielectric was7x10-5 J, what is the relative permittivity er of the dielectric?
