you just anwsered my question but I'm very confused. I missing someting going from going from 6x 1/6, van you please explain what you do there?

you just anwsered my question but I'm very confused.

I missing someting going from going from 6x 1/6, van you please explain what you do there?

x cos(3x^2+ 5)dx 

ˆ ˆ2 cos 3x2 + 5 x dx x cos 3x + 5 dx = Let u be the argument of the cosine function: u = 3x2 + 5 Differentiate this expression. The derivative of u is du and the derivative of 3x2 + 5 is 6x...