+ + + [1] 0 . 5989547 o(F)/u(F). gt; 100 lt;- NULL [1] 0. 0009916873 gt; sd (x) /mean (x) gt; for (i in 1:200) { xi lt;- x[-i] x 2 0). Show that...

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+++[1] 0 . 5989547o(F)/u(F).> 100 <- NULL[1] 0. 0009916873> sd (x) /mean (x)> for (i in 1:200) {xi <- x[-i]x 2 0). Show that CV(F) = 1.> 199*sum((loo-mean (100) ) ~ 2)/200100 <- c(loo, sd(xi)/mean (xi) )distribution is 1.96 and its 0.95 quantile is 1.645.)based on 200 observations contained in a vector x.od soilanGive an approximate 95% confidence interval for CV(F). (The 0.975 quantile of a N(0, 1)(b) The following R code computes that jackknife standard error of an estimate of CV(F)4. [10 marks] Suppose that X1, . . ., Xn are positive random variables from a cdf F with(a) Suppose that F is an Exponential distribution (whose pdf is f(x; A) = A exp(-Ax) formean u(F) and variance o?(F). The coefficient of variation of F is defined by CV(F) =