#1 For which reactions I) O2(g)+H2(g)H2O2(l) II) C(s, diamond) + O2(g) CO2(g) III) N2(l) + 3 F2(g) 2 NF3(l) IV) C(s, graphite) + 3/2 O2(g) + H2(g)

#1 For which reactions I) O2(g)+H2(g)→H2O2(l)II) C(s, diamond) + O2(g) → CO2(g)III) N2(l) + 3 F2(g) → 2 NF3(l)IV) C(s, graphite) + 3/2 O2(g) + H2(g) →CO2(g) + H2O(g)V) 2 Fe(s) + 3/2 O2(g) → Fe2O3(s) would ∆Hr◦ = ∆Hf◦?#2Use these three reactionsCH4(g) + 2 O2(g) −→ CO2(g) + 2 H2O(g)∆H◦ = −802 kJ CH4(g) + CO2(g) −→ 2 CO(g) + 2 H2(g)∆H◦ = 247 kJ CH4(g) + H2O(g) −→ CO(g) + 3 H2(g)∆H◦ = 206 kJto determine the appropriate enthalpy of change ofCH4(g)+3/2 O2(g)−→CO(g)+2H2O(g).#3 Remember to calculate to the correct number of sig figs.Given the following thermodynamic data,2H2O(g) → O2(g) + 2H2(g)∆Hrxn = 483.6kJH2O(g) → H2O(l) ∆Hrxn = −44.0kJWhat is the molar heat of formation for liquid water, H2O (l)?Answer in units of kJ/mole.