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1:Find the roots of the function \(f(x)=2x^2+3x-7\) using the quadratics formula. \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) where : \(a=2\) \(b=3\) \(c=-7\) 2: Find the values of \(x\) a
1:Find the roots of the function \(f(x)=2x^2+3x-7\) using the quadratics formula.
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) where :
\(a=2\)
\(b=3\)
\(c=-7\)
2: Find the values of \(x\) and \(y\) using subsitution method.
\(3x^2-5xy+2y^2=33\)
\(4x-3y=14\)
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- ANSWER
We will find the roots of the function\(f(x) = 2x^2+3x-7\)
First, we will determine whether the equation can be factorised.
This expression cannot be factorised. Therefore, the general quadratic formula can be used.
Secondly, we identify the coefficients in the equation for use in the formula
From the equation:
\(a=2\)
\(b=3\)
\(c=-7\)
Thirdly, we will apply the quadratic formula.
We always write the formula first and then, substitute the values of and
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(= {-3 \pm \sqrt{3^2-4(2)(-7)} \over 2(2)}\)
\( = {-3 \pm \sqrt{65} \over 4}\)
Lastly, we write the final answer
The two roots of function \(f(x)=2x^2+3x-7\)are \(1.266\) and \(-2.675\)
