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QUESTION
2C8H18(g) + 25O2(g) --gt; 16CO2(g) + 18H2O(g) 0.400 mol of octane is allowed to react with 0.600 mol of oxygen. Which is the limiting reactant? How
2C8H18(g) + 25O2(g) --> 16CO2(g) + 18H2O(g)0.400 mol of octane is allowed to react with 0.600 mol of oxygen. Which is the limiting reactant?How many moles of water are produced in this reaction?After the reaction, how much octane is left?
